Question

Medal
According to the following reaction, how many grams of copper(II) chloride are required for the complete reaction of 29.5 grams of silver nitrate?

silver nitrate (aq) + copper(II) chloride (s) silver chloride (s) + copper(II) nitrate (aq)

? grams copper(II) chloride

Answer 1

please anyone help me

Answer 2

29.5g/Molar mass of Silver Nitrate = n. Assuming that silver nirate is the limiting reactant. multiply n by the molar mass of copper(II) chloride. then you'll have grams of copper(II) chloride

Answer 3

Is the equation balanced? The answer that I gave assumes that both copper(ii)chloride and silver nitrate have a coefficient of 1

Answer 4

yes its balanced

Answer 5

And is the coefficient 1 and 1?

Answer 6

yes

Answer 7

So what answer did you get, and does it match your answer sheet?

Answer 8

i dont have a answer sheet

Answer 9

what do you think the answer is

Answer 10

I have the answer. But I want you to try it and post your answer. Then'll give you the answer.

Answer 11

Follow the formula that I gave you above.

Answer 12

okay

Answer 13

what are the step to it

Answer 14

29.5g/Molar mass of Silver Nitrate = n. Assuming that silver nirate is the limiting reactant. multiply n by the molar mass of copper(II) chloride. then you'll have grams of copper(II) chloride

Answer 15

4793.75

Answer 16

am i right?

Answer 17

Try again. So it'll be 29.5 (divided by ) Molar mass of silver nitrate, which will give us moles of silver nitrate. Since the coefficient is 1 to , we multiply it by 1(which doesn't make a difference to our answer), then we can multiply the moles of silver nitrate by molar mass of copper(ii) chloride, which will give us grams of copper (ii) chloride. try this method and post your answer

Answer 18

169.01 is molar mass

Answer 19

169.87 sorry

Answer 20

yes, so plug that into the equation and find moles and then multiply by molar mass of copper(ii)chloride. continue you're almost there!

Answer 21

27603.87

Answer 22

am i right

Answer 23

\[ \frac{ 29.5g }{ Molar mass of Silver Nitrate } = n ...... Grams of Copper(ii) Chloride = n * Molar mass of Copper (ii) Chloride\]

Answer 24

n should be a very small number

Answer 25

0.173

Answer 26

Good thats the value of n

Answer 27

Now use that to find grams

Answer 28

28.11

Answer 29

what was the molar mass that you used for copper (ii) chloride?

Answer 30

162.5

Answer 31

well the molar mass of Copper(II) chloride is 134.45g/mol. try multiplying your n with this number to see what you get.

Answer 32

23.25

Answer 33

Yes you're right!

Answer 34

so is that my answer?

Answer 35

Yes

Answer 36

in grams

Answer 37

thxx :)