Medal .. Please help how many grams of oxygen gas are required for the complete reaction of 24.2 grams of benzene (C6H6)? benzene (C6H6) (l) + oxygen (g) carbon dioxide (g) + water (g) ? grams oxygen gas
1.) Balance the equation 2C6H6+15O2->12CO2+6H20 2.) Get moles of C6H6 24.2gramC6H6 * 2mole C6H6 78.112g C6H6 moles C6H6= .61957 3.) Get moles of O2, convert moles of C6H6 to O2 moles 0.61957 C6H6* 15 O2 moles 2 mole C6H6 moles O2= 4.6481 4.) 4.6481 moles O2 * 32.00 grams O2 15 moles O2 O2 grams= 9.91
i finished this question but can you please help me on another question please
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