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Trigonometry 15 Online
OpenStudy (anonymous):

Use the law of cosines to find the value of cos theta. Round your answer to two decimal places.

OpenStudy (anonymous):

OpenStudy (campbell_st):

well to start \[\cos^(\theta) = \frac{b^2 + c^2 - a^2}{2bc}\] a is the side opposite the required angle... theta b and c are the sides that make the angle just substitute and calculate hope it helps

OpenStudy (anonymous):

I got 1.24, although none of my answer choices are these. . .

OpenStudy (anonymous):

oops, I accidentally added side a. I got 0.22 and that is one of the answer choices

OpenStudy (anonymous):

Thank you! :)

OpenStudy (campbell_st):

well there is an error as the cos of any angle has a range of -1 <= cos(theta) < = 1 so \[\cos(\theta) = \frac{5.7^2 + 9.8^2 - 10.2^2}{2 \times 5.7 \times 9.8}\]

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