Question

does anyone know how to solve this??
2log(base2) (x+1) = log(base2) 2+1
please help

Answer 1

\[2* \log_{2} (x+1)=\log_{2} 2 +1\]

Answer 2

so by log base property of if base and number are same thn result will be same

Answer 3

\[\log_{a} a=1\] alwys

Answer 4

\[\log_{2} 2=?????\]

Answer 5

@AdrianaPerez

Answer 6

im a little confused, i understand that when they are both the same its 1

Answer 7

What would be the steps?

Answer 8

\[\log_{2} 2=1\]

Answer 9

\[2*\log_2(x+1)=1+1=2\]

Answer 10

divide both side by 2

Answer 11

\[\log_2(x+1)=1\]

Answer 12

it will be 1 when both base and number are equal
as base=2
so number must be =2
x+1=2
subtract 1 from both side