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Trigonometry
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Factor, the simplify. sin^3(x)-sin^2(x)-sinx+1
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\[\sin^2x(sinx-1)-1(sinx-1)\]
take sinx-1 out
and can that be simplified further?
= (sinx - 1)(sin^2 x - 1) - now you can factor the second parentheses
- its the difference of 2 squares
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the second parentheses would be sin(x) +1 * sin(x) -1
Yes : So, finally you will get like: \[(\sin(x) - 1)(\sin(x) + 1) (\sin(x)-1) \implies (\sin(x)-1)^2(\sin(x)+1)\]
thanks!
check the attachment
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