how would I solve this? x = 5 sin t, y = 5 cos t
you want to eliminate 't' ? just square and add them
square them and add
sin^2t+cos^2t=1 trigonometry formula
so i sq them both?
wait what?
yes find x^2 and y^2
\(x =5 \sin t \\ x^2 = (5 \sin t)^2 = ... ?\)
ok 25 sin^2 but how do i add them
y^2 = 25 cos^2 t now add them \( x^2 +y^2 = 25 \sin^2 t +25 \cos^2 t\) what can you factor out ??
25 and t
note that sin t and cos t are functions and are not separate entities like 'sin' and 't' so you cannot factor out t :)
just factor out 25 and see what u get
and use the fact that \( \sin^2 t + \cos^2 t =1\)
so it would be a circle
yes
what would be the radius of that circle ?
5
but what does this mean: Eliminate the parameter t from the following.
It means to do what you just did. you now have x^2 + y^2 = 5^2 no t !
no cos or sin?
no 't'
eliminate 't' means combine the equations in such a way that the new equation does not have the variable 't' at all
so the answer looks like this 5sin^2 +5cos^2
no
geez i dont get it
\(\sin^2 t +\cos^2 t\) is already 1
oh yeah
25 (sin^2 t + cos^2 t) = 25*1 =25
25 (sin^2 t + cos^2 t) = 25
thats what they are asking for?
I think they are asking for you to change x = 5 sin t, y = 5 cos t into x^2 + y^2 = 25
^^
the first form x = 5 sin t, y = 5 cos t is "parametric form" you can calculate (x,y) pairs for values of "t" the other form x^2 + y^2 = 25 has no "t". You can still find (x,y) pairs, but it is a bit more painful
thank you so much thanks for your brilliance
If you want more background, see https://www.khanacademy.org/math/precalculus/parametric_equations and look at the first video in each section.
will do
and the 3rd video in the first section looks close to your problem https://www.khanacademy.org/math/precalculus/parametric_equations/parametric/v/parametric-equations-3 The first 2 videos talk about the parametric form... which is useful if the idea is new.
well i am stuck on a another problem if you guys are up for the challenge
Find all solutions if 0 ≤ x < 2π. Use exact values only. (Enter your answers as a comma-separated list.) sin x cos 2x + cos x sin 2x = 1/2
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