Question

If I'm finding Ci for pi/6, so that it's ((pi/6)+((pi/6)-1) / 2): How do I subtract 1 from pi/6 to get it in terms of pi? The answer should be pi/12

Answer 1

you want to do pi/6-1?

Answer 2

find a common denominator

Answer 3

\[\frac{\pi}{6}-1 \\ \frac{\pi}{6}-\frac{6}{6}\]

Answer 4

you can combine the fractions now

Answer 5

So I'm getting pi - 6 divided by 6?

Answer 6

if you want to write pi/6-1 as one term
yes you get (pi-6)/6

Answer 7

I don't know what Ci means

Answer 8

and it looks like you have another pi/6 up there and something is being divided by 2

Answer 9

What I'm doing is using the midpoint rule to approximate a definite integral, Ci gives midpoints

Answer 10

I need to solve the entire thing where I will only have pi/12, which is equal to pi/6 + (pi/6 - 1) all over 2

Answer 11

I just don't know how to get it in terms of 'nice' pi

Answer 12

So it's \[\int\limits_{0}^{\pi} \sin x^2 dx\]

and solving using the midpoint rule with n = 6

Answer 13

we need the midpoint of each of these intervals