Question

non-right triangle
Solve the missing sides and angles.. please help angle A= 30, side a = 3, and side c=6?

Answer 1

now use trig ratios to find the other side

Answer 2

I have to use law of sines and cosines to find missing angles and sides.... for one of the angles I got a 90 degree, it should be a non-right triangle.. I was hoping to see why I got that angle..... can some one please help me out...
I need to know because I have a quiz over this

Answer 3

In an non right triangle, there are six unknowns: the three angle measures and the three side lengths. To solve an oblique triangle you need one of the following sets of information:
Two sides and an angle opposite one of the known sides
Two angles and any side
Two sides and their included angle
All three sides
If you know either (1) or (2), you can use the law of sines to solve the triangle. If you know (3) or (4), you must tag-team with the law of cosines and then the law of sines to find the solution.

Answer 4

for Laws of sine and cosine
read this
http://www.sparknotes.com/testprep/books/sat2/math2c/chapter9section9.rhtml

Answer 5

angle C= 90, Angle B= 60 ??

Answer 6

Law of sine
\[a/ \sin (A) = c / \sin (C)\]
\[3/\sin (30) = 5/\sin(C)\]
\[3/(1/2) = 5/\sin(C)\]
\[5/6 = \sin(C)\]
Noe you can find \[\sin^{-1} (5/6)\]

Answer 7

how about the sides?

Answer 8

by cosin law?

Answer 9

side b= 6.87

Answer 10

RIGHT?

Answer 11

C=6 NOT 5

Answer 12

Sure??? Cause then
\[6= 6/\sin(C)\]
\[C= \sin^{-1} (6/6)\]
\[C= \sin^{-1} (1)\]

then C = 90 degree

Answer 13

could it be 90 degree and the whole function has to be non right trianfle