Question

Find dy dx by implicit differentiation: e^y sinx = x + y .

Answer 1

e y^(e-1) dy/dx * sin x + y^e * cos x = 1 + dy/dx
now make dy/dx the subject

Answer 2

do you have \(\large \rm y^{esinx}=x+y\)

Answer 3

I think the original problem is either

\[\Large e^y * \sin(x) = x + y\]

or

\[\Large e^{y*\sin(x)} = x + y\]