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Mathematics 15 Online
OpenStudy (anonymous):

Algebra Factoring question Will Give Fan and Medal!

OpenStudy (anonymous):

A sandbag was thrown downward from a building. The function f(t) = -16t^2 - 32t + 384 shows the height f(t), in feet, of the sandbag after t seconds: Part B: Complete the square of the expression for f(x) to determine the vertex of the graph of f(x). Would this be a maximum or minimum on the graph? Part C: Use your answer in part B to determine the axis of symmetry for f(x)?

OpenStudy (anonymous):

@ganeshie8 @iambatman

OpenStudy (anonymous):

@bohotness can you help?

OpenStudy (bohotness):

go to brain fuse tulsa library look on google idk the answer their help you :)

OpenStudy (anonymous):

Okay, Thank you tho @bohotness

OpenStudy (anonymous):

@jim_thompson5910 do you think you can help?

OpenStudy (bohotness):

yw

jimthompson5910 (jim_thompson5910):

-16t^2 - 32t + 384 or -16x^2 - 32x + 384 is in the form ax^2 + bx + c what are the values of 'a', 'b', 'c' ?

OpenStudy (anonymous):

a=-16 b=-32 c=384

jimthompson5910 (jim_thompson5910):

plug a = -16 and b = -32 into the formula x = -b/(2a) and tell me what you get

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

I got 1 as my answer

jimthompson5910 (jim_thompson5910):

close but no

OpenStudy (anonymous):

did I get the sign wrong?

jimthompson5910 (jim_thompson5910):

yeah you lost a sign somewhere

OpenStudy (anonymous):

oh okay then it would come out as -1

OpenStudy (anonymous):

sorry about that

jimthompson5910 (jim_thompson5910):

the x coordinate of the vertex is -1

jimthompson5910 (jim_thompson5910):

plug x = -1 into y = -16x^2 - 32x + 384 to get the y coordinate of the vertex

OpenStudy (anonymous):

okay, But what does it mean in the question with complete the square?

jimthompson5910 (jim_thompson5910):

what do you get for y?

OpenStudy (anonymous):

336

jimthompson5910 (jim_thompson5910):

incorrect

OpenStudy (anonymous):

oh wait sorry

OpenStudy (anonymous):

would it be 400?

jimthompson5910 (jim_thompson5910):

yes so the vertex is (-1,400)

jimthompson5910 (jim_thompson5910):

in general, the vertex is (h,k) so h = -1 and k = 400

jimthompson5910 (jim_thompson5910):

vertex form is y = a(x-h)^2 + k

jimthompson5910 (jim_thompson5910):

the value of 'a' is already given (a = -16)

OpenStudy (anonymous):

so now plug in the values into the equation?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

okay so it would be y=-16(x-(-1)0^2+400 What would be x? or is it not given?

jimthompson5910 (jim_thompson5910):

x is a variable and it is unknown (and can change)

jimthompson5910 (jim_thompson5910):

so the equation is either y = -16(x - (-1))^2 + 400 or y = -16(x +1)^2 + 400 the simplified version is always best

jimthompson5910 (jim_thompson5910):

you could optionally change x to t and change y to f(t) but that's a trivial step really

OpenStudy (anonymous):

So the answer to part B would be y = -16(x +1)^2 + 400

jimthompson5910 (jim_thompson5910):

well they say to complete the square. That gives you y = -16(x +1)^2 + 400 or f(t) = -16(t +1)^2 + 400

jimthompson5910 (jim_thompson5910):

you then use this to determine the vertex which is (-1,400)

jimthompson5910 (jim_thompson5910):

but you found the vertex first to get the vertex form

jimthompson5910 (jim_thompson5910):

they ultimately want the vertex and want to know if it is a min or max

OpenStudy (anonymous):

it would be maximum since y is positive. But the question says something about comlpeting the square.. How would I do that? Or have we already done it?

jimthompson5910 (jim_thompson5910):

when you go from -16x^2 - 32x + 384 to y = -16(x +1)^2 + 400 you have completed the square

jimthompson5910 (jim_thompson5910):

there is another method, but I don't like that method because it's a lot uglier in general

jimthompson5910 (jim_thompson5910):

so when you go from standard form y = ax^2 + bx + c to vertex form y = a(x-h)^2 + k, you have completed the square

jimthompson5910 (jim_thompson5910):

btw, it's not a max because y is positive it is a max because 'a' is negative. a = -16 a < 0 'a' is negative which means the vertex is a maximum point

jimthompson5910 (jim_thompson5910):

the negative 'a' value graphs an upside down parabola with the max point at the very top |dw:1414975262470:dw|

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