Algebra Factoring question Will Give Fan and Medal!
A sandbag was thrown downward from a building. The function f(t) = -16t^2 - 32t + 384 shows the height f(t), in feet, of the sandbag after t seconds: Part B: Complete the square of the expression for f(x) to determine the vertex of the graph of f(x). Would this be a maximum or minimum on the graph? Part C: Use your answer in part B to determine the axis of symmetry for f(x)?
@ganeshie8 @iambatman
@bohotness can you help?
go to brain fuse tulsa library look on google idk the answer their help you :)
Okay, Thank you tho @bohotness
@jim_thompson5910 do you think you can help?
yw
-16t^2 - 32t + 384 or -16x^2 - 32x + 384 is in the form ax^2 + bx + c what are the values of 'a', 'b', 'c' ?
a=-16 b=-32 c=384
plug a = -16 and b = -32 into the formula x = -b/(2a) and tell me what you get
okay
I got 1 as my answer
close but no
did I get the sign wrong?
yeah you lost a sign somewhere
oh okay then it would come out as -1
sorry about that
the x coordinate of the vertex is -1
plug x = -1 into y = -16x^2 - 32x + 384 to get the y coordinate of the vertex
okay, But what does it mean in the question with complete the square?
what do you get for y?
336
incorrect
oh wait sorry
would it be 400?
yes so the vertex is (-1,400)
in general, the vertex is (h,k) so h = -1 and k = 400
vertex form is y = a(x-h)^2 + k
the value of 'a' is already given (a = -16)
so now plug in the values into the equation?
yes
okay so it would be y=-16(x-(-1)0^2+400 What would be x? or is it not given?
x is a variable and it is unknown (and can change)
so the equation is either y = -16(x - (-1))^2 + 400 or y = -16(x +1)^2 + 400 the simplified version is always best
you could optionally change x to t and change y to f(t) but that's a trivial step really
So the answer to part B would be y = -16(x +1)^2 + 400
well they say to complete the square. That gives you y = -16(x +1)^2 + 400 or f(t) = -16(t +1)^2 + 400
you then use this to determine the vertex which is (-1,400)
but you found the vertex first to get the vertex form
they ultimately want the vertex and want to know if it is a min or max
it would be maximum since y is positive. But the question says something about comlpeting the square.. How would I do that? Or have we already done it?
when you go from -16x^2 - 32x + 384 to y = -16(x +1)^2 + 400 you have completed the square
there is another method, but I don't like that method because it's a lot uglier in general
so when you go from standard form y = ax^2 + bx + c to vertex form y = a(x-h)^2 + k, you have completed the square
btw, it's not a max because y is positive it is a max because 'a' is negative. a = -16 a < 0 'a' is negative which means the vertex is a maximum point
the negative 'a' value graphs an upside down parabola with the max point at the very top |dw:1414975262470:dw|
Join our real-time social learning platform and learn together with your friends!