Question

George tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes the denominator zero, and you can't divide by zero," George explains. Using complete sentences, demonstrate to George how the equation is still solvable

Answer 1

ok... here is a simple example

\[\frac{1}{ x-1 }\]

looking at the equation

the denominator will be zero when x = 1

and as stated in the question dividing by zero is undefined.

What you do is restrict the domain, or the x values that you can use...


I this example you say you can input all real x values, except x = 1

that means you can solve it or graph it... but the restriction will cause a gap..

hope it makes sense.

Answer 2

not really can u explain it more

Answer 3

okay i gt the answer frm this website
on the bottom there is a drawing look at it
http://openstudy.com/study#/updates/53078582e4b00fb1e237bd91