Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

@jim_thompson5910 I got 519.05 for the lateral area , however that's not one of the pi choices..

jimthompson5910 (jim_thompson5910):

what is the radius of the new cone?

OpenStudy (anonymous):

r= 9 h= 16 Is what I plugged in

jimthompson5910 (jim_thompson5910):

hint: you'll have a second cone that is similar to the first cone

jimthompson5910 (jim_thompson5910):

"similar" as in "similar triangles" (the geometric definition of "similar")

jimthompson5910 (jim_thompson5910):

|dw:1414976625040:dw| solve for x

jimthompson5910 (jim_thompson5910):

x is the radius of the larger new cone

OpenStudy (anonymous):

x= 12

jimthompson5910 (jim_thompson5910):

now r = 12 and the slant height, call it s, is s = 16 |dw:1414976947964:dw|

jimthompson5910 (jim_thompson5910):

what is the lateral surface area of this cone shown below (in terms of pi)? |dw:1414977000151:dw|

OpenStudy (anonymous):

753.98

OpenStudy (anonymous):

@jim_thompson5910 There is no pi option for that answer... There's only 653 :/

jimthompson5910 (jim_thompson5910):

how did you get 653?

OpenStudy (anonymous):

No, my answer is above that comment.

jimthompson5910 (jim_thompson5910):

how did you get 753.98 ?

OpenStudy (anonymous):

jimthompson5910 (jim_thompson5910):

but we don't know h

jimthompson5910 (jim_thompson5910):

the good news is that \(\Large s = \sqrt{h^2 + r^2}\)

jimthompson5910 (jim_thompson5910):

so the formula reduces down to \(\Large \pi*r*s\)

OpenStudy (anonymous):

I thought that h=16 ?

jimthompson5910 (jim_thompson5910):

no s = 16

jimthompson5910 (jim_thompson5910):

go back to the drawing |dw:1414977601271:dw|

jimthompson5910 (jim_thompson5910):

we could find h and use the formula you posted, but that's extra unneeded work

jimthompson5910 (jim_thompson5910):

|dw:1414977643434:dw|

jimthompson5910 (jim_thompson5910):

height and slant height are 2 different things

OpenStudy (anonymous):

Oh! That's what confused me, I got 192pi .

jimthompson5910 (jim_thompson5910):

which is the correct answer

OpenStudy (anonymous):

:)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!