Ask your own question, for FREE!
Mathematics 93 Online
OpenStudy (anonymous):

Impossible math problem someone help its attached below

OpenStudy (anonymous):

OpenStudy (anonymous):

\[f\circ g(x)=f(g(x))\] which in this case is \[f(-\frac{2}{x})\]

OpenStudy (anonymous):

since \[f(\spadesuit)=\frac{\spadesuit}{\spadesuit-5}\] you have \[f(-\frac{2}{x})=\frac{-\frac{2}{x}}{-\frac{2}{x}-5}\]

OpenStudy (anonymous):

get rid of annoying complex fraction by multiplying top and bottom by \(x\) go get \[\frac{-2}{-2-5x}\]

OpenStudy (anonymous):

or if you prefer, more simply \[\frac{2}{2+5x}\]

OpenStudy (anonymous):

2/5x+2

OpenStudy (anonymous):

sorry wasnt supposed to solve that

OpenStudy (anonymous):

as for the domain, the domain of \(g\) is all numbers except 0 and the domain of \(f\circ g\) is therefore all numbers except 0 and \(-\frac{2}{5}\)

OpenStudy (anonymous):

how would I state that in interval notation though?

OpenStudy (anonymous):

i gave up

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!