Question

Impossible math problem someone help its attached below

Answer 1

\[f\circ g(x)=f(g(x))\] which in this case is
\[f(-\frac{2}{x})\]

Answer 2

since
\[f(\spadesuit)=\frac{\spadesuit}{\spadesuit-5}\] you have
\[f(-\frac{2}{x})=\frac{-\frac{2}{x}}{-\frac{2}{x}-5}\]

Answer 3

get rid of annoying complex fraction by multiplying top and bottom by \(x\) go get
\[\frac{-2}{-2-5x}\]

Answer 4

or if you prefer, more simply
\[\frac{2}{2+5x}\]

Answer 5

2/5x+2

Answer 6

sorry wasnt supposed to solve that

Answer 7

as for the domain, the domain of \(g\) is all numbers except 0 and the domain of \(f\circ g\) is therefore all numbers except 0 and \(-\frac{2}{5}\)

Answer 8

how would I state that in interval notation though?

Answer 9

i gave up