Algebra help?? WTF??
What the heck would be a better choice of language but what do you need
shouldn't it be:\[-\frac{ 56 }{ 65 }=1-2\sin ^{2}\Theta\]\[-\frac{ 56 }{ 65 }-1=-2\sin ^{2}\Theta\] \[-\frac{ 1 }{ 2 }(-\frac{ 56 }{ 65 }-1)=\sin ^{2}\Theta\]
I'm not understanding this simple algebra that they are doing and it's frustrating me--you cant just move the "1 -" to the left. You have to add the one! I don't get it, i've been trying to figure this out for a long time.
yeah they made a bad typo. You subtract 1 from both sides and then divide both sides by -2 (or multiply both sides by -1/2)
it should end up with sin^2(theta) = 121/130 and NOT sin^2(theta) = -121/130
thank you so much, I thought I was going crazy but I understand it now.
you're welcome
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