The grimsley inn has 250 rooms and the standard rate is $150 per night per room. During the non-holiday season, 100 rooms are booked each day on average. But, for each $20 price reduction, 25 more rooms will be rented. What non-holiday price should be advertised?
@aum @freckles
@jim_thompson5910
Assume price reduction of n * 20. Rate per night = 150 - 20n Number of rooms booked = 100 + 25n Total revenue R = (150 - 20n) * (100 + 25n) Maximize R. Find dR/dn, equate to zero and solve for n.
or simply find the vertex of quadratic
they tricky part is setting up revenue function as u can see
wait, so what do we do with the 250 rooms
That is a constraint on the max rooms that can be rented.
100 + 25n <= 250
lol what does that mean?
n <= 6.
is it possible to have 250 instead of 25 ?
When finding the "n" that gives maximum revenue, if n exceeds 6, then you have to stop at n = 6.
okay it's making a bit more sense. But I am not completing understanding how we got 100+25n
"for each $20 price reduction, 25 more rooms will be rented." If price reduces by 20*n, then 25*n more rooms will be rented. "More" here refers to more than average number of rooms rented when the rate is standard. That is 100 rooms + 25*n rooms.
oh okay
Thank you!
You are welcome.
Join our real-time social learning platform and learn together with your friends!