Question

The slope of the line tangent to the graph of ln(xy) = x at the point where x=1 is...

Answer 1

slope is given by dy/dx so diffrentiate ln(xy) with respect to x

Answer 2

This is an extra credit problem because we haven't worked with ln. I'm a quick study, we just haven't learned this yet

Answer 3

u know how to diffrentiate

Answer 4

I'm not sure how to differentiate ln

Answer 5

diffrentiation of lnx is 1/x

Answer 6

here 1/xy(dy/dx)=1

Answer 7

Oh, okay, so the slope is 1?

Answer 8

1/xy(dy/dx)=1
I assumed that that meant the slope is 1

Answer 9

Okay, continue please

Answer 10

There's 0, 1, e, e^2, and 1-e for the options

Answer 11

@perl

Answer 12

hello

Answer 13

@gorv

Answer 14

Perl would you mind explaining how to do this problem? @danish071996 and I have tried a wack at it but are stumped

Answer 15

implicit derivative
1/(xy) * (1*y + x* y' ) = 1

Answer 16

That just all went over my head. I'm sure I'll understand shortly, we haven't done ln in class yet, this is an extra credit homework problem