Which set of vertices forms a parallelogram?
A(2,4), B(3, 3), C(6, 4), D(5, 6) A(-1, 1), B(2, 2), C(5, 1), D(4, 1) A(-5, -2), B(-3, 3), C(3, 5), D(1, 0) A(-1, 2), B(1, 3), C(5, 3), D(1, 1)
@uri @Conqueror @animal_lover36 @PaulaLovesSchool13
any ideas?
I was thinking the second one
@Kainui @iambatman @shinalcantara @Kidthatbro8
why won't you graph to find out? ^_^
you can also use the distance formula to find out
\[d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\]
@beacon239 Do you have a reason for thinking the second one? For lines to be parallel they have the same slope To find the slope between two points you need to calculate this: (difference in y) / (difference in x) For instance in the first option A = (2,4) B= (3,3) so the slope is (4-3)/(2-3) = 1/-1 =-1 You need to work out the slope of the opposite side (CD) You need to do that for all the options and find the answer where BOTH pairs of opposite sides have the same slope. @shinalcantara The distance is not relevant to this solution - your equation gives the distance between points - but it is th eslope which matters
@beacon239 If you want to show any work then I will help.....
the distance formula does matter. it won't be a parallelogram if the opposite sides are not having the same length though.. (-_-)!
if BOTH pairs of opposite sides are parallel then they WILL have the same length
It IS true that you could work out wheher ONE pair of opposites is parallel AND have the same length - that also proves a parallelogram
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