Solve and graph the absolute value inequality |4x+1|≤5
≤
less than or equal to
5
Question 3 (Worth 1 points) [02.06] Solve and graph the absolute value inequality: |4x + 1| ≤ 5. number line with closed dots on −1.5 and 1 with shading going in the opposite directions. number line with open dots on −1.5 and 1 with shading in between. number line with closed dots on −1 and 1 with shading in between. number line with closed dots on −1.5 and 1 with shading in between. Points earned on this question: 0 Question 4 (Worth 1 points) [02.06] Which of the following is the correct graph of the compound inequality 4p + 1 > −11 or 6p + 3 < 39? a number line with closed circles at -3 and 6 and shading in between. number line with open dots at ¨C3 and 6 and shading to the right of 6 and to the left of ¨C3. number line with open dot at ¨C2 and at 5 with shading in between. number line with shading everywhere. Points earned on this question: 0 Question 5 (Worth 1 points) [02.06] Which of the following is an equivalent form of the compound inequality −22 > −5x − 7 ≥ −3? −5x − 7 < −22 and −5x − 7 ≥ −3 −5x − 7 > −22 and −5x − 7 ≥ −3 −5x > −22 and −7 ≥ −3 −5x − 7 < −22 and −5x − 7 ≤ −3 Points earned on this question: 0
|4x+1|≤5 5 - 1 = 4 4x = 4 = 1 x __ 1 do you know what sign would be there?
less than or equal to
\(|4x + 1| \le 5\) This breaks into two inequalities: \(4x + 1 \le 5\) and \(-4x - 1 \le 5\) ---------------- \(4x + 1 \le 5\) Subtract 1 to both sides: \(4x \le 4\) Divide 4 to both sides: \(x \le 1\) ---------------- \(-4x - 1 \le 5\) Add 1 to both sides: \(-4x \le 6\) Divide -4 to both sides, and we get \(-\dfrac{6}{4}\), can you simplify that? @lopez9407
let's test it. lets to -2 = x. can you solve this for me?
Can you simplify \(-\dfrac{6}{4}\)? @lopez9407
x=-2
-3/2
I am confused guys i need that on a linear graph
Please help me I got it wrong on my exam and want to know why one this one and two more problems. HELP!!!!
1.5
Yep, you got it! @lopez9407 So your answers are: \(x \le 1\) and \(x \ge -\dfrac{3}{2}\)
Understand, @lopez9407 ?
When i have a problem is doing the linear graph the answers are up here
This is what your graph looks like.
I know how to solve it the part i do not get is how to graph it in the linear graph correctly
That's the linear graph above, when you graph the two solutions, the overlap area will be your solutions.
<--------------------> in a graph like this is the one i do no understand how to do it
Join our real-time social learning platform and learn together with your friends!