Tutorial: Slope
\(\huge\bf Types~of~Slope:\) \(\bf\small Positive~Slope:\) Positive slope rises from LEFT to RIGHT. \(\bf\small Negative~Slope:\) Negative slope declines from LEFT to RIGHT. Examples of Positive and Negative Slopes: http://www.shmoop.com/images/prealgebra/unit6/pa.6.195.png \(\bf\small No~ Slope:\) Lines with no slope are horizontal, and parallel to the x-axis. Example: http://dj1hlxw0wr920.cloudfront.net/userfiles/wyzfiles/fef7b984-29f7-468a-b78a-2cb5a2124bf9.gif \(\bf\small Undefined~Slope:\) Lines with undefined slope are vertical, and parallel to the y-axis. Example: http://www.wtamu.edu/academic/anns/mps/math/mathlab/col_algebra/col_alg_tut27ex5c.gif \(\huge\bf Finding~Slope:\) There are 3 different ways to find slope. \(\bf Equations:\) Some equations just give you the slope, for example: \(\bf\small Slope-intercept~form:\) \(y = \color{lime}mx + \color{blue}b\) Where \(\color{lime}m\) = slope, and \(\color{blue}b\) = y-intercept. So if we have: \(y = \color{lime}2x + \color{blue}5\) Our slope will be \(\color{lime}2\). \(\bf\small Point-Slope~form:\) \(y - \color{blue}{y_1} = \color{lime}{m}(x -\color{yellow}{ x_1})\) Where \(\color{lime}m\) = slope, \(\color{blue}{y_1}\) = y-value on the line, and \(\color{yellow}{x_1}\) = x-value on the line. So if we have: \(y - \color{blue}5 = \color{lime}5(x - \color{red}2)\) Our slope will be \(\color{blue}5\). But some equations like: \(\bf\small Standard~form:\) \(Ax + By = C\) To find the slope of the equation, we have to rearrange it into slope-intercept form(\(y = \color{lime}mx + \color{blue}b\)). So if we have: \(2x + 3y = 6\) First, we subtract 2x to both sides: \(3y = -2x + 6\) Now we divide 3 to all terms: \(y = \color{lime}{-\dfrac{2}{3}}x + \color{blue}2\) Now we can see that the slope of the equation is \(\color{lime}{-\dfrac{2}{3}}\), and the y-intercept is \(\color{blue}2\). \(\bf Graph:\) Slope is also defined as: \(\dfrac{Rise}{Run}\). We can see this on graphs of lines. \(\bf\small Rise:\) Rise represents the numerator of the slope(ex: In \(m = \dfrac{1}{2}\) 1 is the rise). Rise can be either going up or down, where up brings a positive number and down brings a negative. \(\bf\small Run:\) Run represents the denominator of the slope(ex: In \(m = -\dfrac{4}{5}\) -5 is the run). Graph example: http://img.sparknotes.com/figures/3/393a0f9064f0cef5c349ab5966e8842d/slope.gif We can see that the rise here is \(4\), and the run is \(2\), that means the slope will be \(\dfrac{4}{2}\) which simplifies to \(2\). \(\bf Formula:\) The formula for slope is \(m = \dfrac{y_2-y_1}{x_2-x_1}\). This formula is mostly used to find the slope between two points(ex: (2, 3) and (5, 8)). But it can also be used to find the slope on a graph, where we can just take two points from that graph and plug them in. If we are given: \((\color{red}5,\color{lime} 6)\) and \((\color{yellow}8, \color{blue}{12})\) ^ ^ = \(\color{lime}{y_1}\) ^ ^ = \(\color{blue}{y_2}\) | = \(\color{red}{x_1}\) | = \(\color{yellow}{x_2}\) Plug them into the slope equation: \(m = \dfrac{\color{blue}{y_2}-\color{lime}{y_1}}{\color{yellow}{x_2}-\color{red}{x_1}}\) \(m = \dfrac{\color{blue}{12}-\color{lime}6}{\color{yellow}8-\color{red}5}\) Subtract the terms in the numerator and the denominator: \(m = \dfrac{6}{3}\) Simplify by dividing: \(m = 2\) Therefore the slope between \((5, 6)\) and \((8, 12)\) is \(\color{red}2\).
It should be: "Our slope should be \(\color{lime}5\)." not "Our slope should be \(\color{blue}5\)."
I made this because SO many people ask questions about Slope.
Congratulations @iGreen for making this tutorial. There are so many people that need help on slope. I am sure many people will appreciate your hard work.
Thanks @confluxepic , :)
I would use darkgoldrenrod, or just goldenrod as a color instead of yellow, because it is not so well seen, but a GREAT TUTORIAL. I like it:)
@iGreen Those lazy people just want ansurs,Others attend their school lectures attentively..but yes this may help a lot of people. Good job. :)
Thanks! @SolomonZelman It means a lot, you've helped me a lot in the past. Thanks for the tip too.
Yep, that's true. @uri
yw...
Neat work ! Keep it up
Thanks, @Abhisar
@iGreen Ironically, I was just going over slope in algebra this past week. My teachers just couldn't get me to understand. This tutorial has helped me. Thanks!!!!
No problem! I'm glad it helped!
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