A tank of water holding 528 kL of water begins to empty at a rate of 10 kL/min. At the same time, another tank, which is empty, begins to fill at a rate of 14 kL/min. Let k represent the number of kiloliters of water and let t represent time in minutes. The system models this situation. How long will it take for the tanks to hold equal amounts of water, and how much water will that be? k = 528 – 10t k = 14t It will take minutes for both tanks to hold equal amounts of water. They will each hold kiloliters.
So basically for them to have equal amounts the k and t must be equal. So we are solving for k and t, use substitution... 14t=528-10t now solve for t
xD sorry wasnt paying attention brb
t then = 132 k=14(132) k = ? t =132 = answers
It will take 22 minutes for both tanks to hold equal amounts of water. They will each hold 308 kiloliters.
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