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Mathematics 7 Online
OpenStudy (anonymous):

ok who can help me ill post the link to the problem just give me a second the first link will be the problem and the second link will be what has to be plugged in

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

i know f^-1 means inverse but I'm lost after that

OpenStudy (amistre64):

how is f(x) defined?

OpenStudy (amistre64):

or in this case, f(r) maybe?

OpenStudy (anonymous):

f(r) is just that the problem is A=pir^2 i know we have to plug in the 4 into the problem but I'm lost after there

OpenStudy (amistre64):

in general: of f and g are inverses then f(g(x)) = x in other words, let A = 4, and solve for r

OpenStudy (anonymous):

ok i understand that but i just can't seem to get a answer that makes sense

OpenStudy (amistre64):

4 = pi (f'(4))^2 4/pi = (f'(4))^2 sqrt(4/pi) = f'(4)

OpenStudy (amistre64):

or seen another similar way f(r) = pi r^2 f(f'(4)) = pi [f'(4)]^2 4 = pi [f'(4)]^2 etc ....

OpenStudy (anonymous):

ok so thats the answer 4= pi[f^(4)]^2

OpenStudy (amistre64):

thats not the answer, that is the setup for how we can determine f'(4)

OpenStudy (anonymous):

oh ok

OpenStudy (amistre64):

in other words, what value of r makes: 4 = pi r^2 a true statement, solve for r

OpenStudy (anonymous):

ok i still have no idea i understand sort of but i still don't understand how to get the answer from that

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