Find the limit as x approaches 0:
2sin^3 3x/-x^3
Any help would be appreciated! Thank you!

Question

Find the limit as x approaches 0:
2sin^3 3x/-x^3
Any help would be appreciated! Thank you!

ganeshie8 · Answer

Hint : $$ \dfrac{\sin^3(3x)}{x^3} = 27 \cdot \dfrac{\sin^3(3x)}{(3x)^3}$$

gorv · Answer

$$\lim_{x \rightarrow 0}\frac{ sinx  }{ x }=1$$

gorv · Answer

does it ring a bell

cwrw238 · Answer

so can we say that limit of sin^3 3x / / 3x^3   has a limit of 1 as x  approaches 0?

cwrw238 · Answer

if so then the required limit is -2 8 27 = -54

cwrw238 · Answer

* -2 * 27 = -54

cwrw238 · Answer

i think this is valid - limits are not my strong point

cassieforlife5 · Answer

So I'm going with -54 on that question. Could you also check my answer? I'm supposed to find the derivative of
f(x)= ((3x^2)/2) -x
I got 3x-1 for my answer

ganeshie8 · Answer

$\LARGE \color{Red}{\checkmark}$

cassieforlife5 · Answer

Thanks to everyone so much!