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Use the information provided to determine ΔH°rxn for the following reaction: ΔH°f (kJ/mol) CH4(g) + 4 Cl2(g) → CCl4(g) + 4 HCl(g) ΔH°rxn = ? CH4(g) -75 CCl4(g) -96 HCl(g) -92
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@ganeshie8
@amistre64
@JFraser
the \(\Delta H_{rxn}\) is always found the same way, by taking the sum of the enthalpies of the products minus the sum of the enthalpies of the reactants
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