Use the given piecewise function to find...
f(x) = x^2+4 if x<1 3 if x=1 x+4 if x>1 Use the given piecewise function to find... \[\lim f(x) _{x \rightarrow1}\] if it exists and determine if this function is continuous or not when x=1
@johnweldon1993
And again, I know the answer is \[\lim _{x \rightarrow 1}f(x)=5\];not continuous.. but im just not sure how to find it
So think of it like this As x approaches 1 how can it approach 1? well it can approach it from the left side of the graph....orrrr we can approach it from the right side of the graph
So...if we approach x from the left side of the graph...we are at values LESS than 1....so we need to use the first part of the piecewise function because x is less than 1 at this time So if we plug in 1, we will get x^2 + 4, 1^2 + 4, 1 + 4 = 5 Great!
Now! if we approach from the right side, we are at values greater than 1...so we need to use that last part of the function because we are >1 so x + 4 becomes 1 + 4 = 5 again this is why we know the limit is 5 when we approach 1
HOWEVER!!!! when we are AT 1....we equal 3 HOW!?!?!?! lol, well this means the function is NOT CONTINUOUS! because how can we be approaching 5 from both sides...and then when we DO get to 1...we equal 3? its impossible that we are on a continuous line
Hope that makes sense?? if not let me know I can think of another way to put it probably ^_^
Sorry, I am reading through it a couple times.. I'm still not getting it :/
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