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Mathematics 7 Online
OpenStudy (suwhitney):

Use the given piecewise function to find...

OpenStudy (suwhitney):

f(x) = x^2+4 if x<1 3 if x=1 x+4 if x>1 Use the given piecewise function to find... \[\lim f(x) _{x \rightarrow1}\] if it exists and determine if this function is continuous or not when x=1

OpenStudy (suwhitney):

@johnweldon1993

OpenStudy (suwhitney):

And again, I know the answer is \[\lim _{x \rightarrow 1}f(x)=5\];not continuous.. but im just not sure how to find it

OpenStudy (johnweldon1993):

So think of it like this As x approaches 1 how can it approach 1? well it can approach it from the left side of the graph....orrrr we can approach it from the right side of the graph

OpenStudy (johnweldon1993):

So...if we approach x from the left side of the graph...we are at values LESS than 1....so we need to use the first part of the piecewise function because x is less than 1 at this time So if we plug in 1, we will get x^2 + 4, 1^2 + 4, 1 + 4 = 5 Great!

OpenStudy (johnweldon1993):

Now! if we approach from the right side, we are at values greater than 1...so we need to use that last part of the function because we are >1 so x + 4 becomes 1 + 4 = 5 again this is why we know the limit is 5 when we approach 1

OpenStudy (johnweldon1993):

HOWEVER!!!! when we are AT 1....we equal 3 HOW!?!?!?! lol, well this means the function is NOT CONTINUOUS! because how can we be approaching 5 from both sides...and then when we DO get to 1...we equal 3? its impossible that we are on a continuous line

OpenStudy (johnweldon1993):

Hope that makes sense?? if not let me know I can think of another way to put it probably ^_^

OpenStudy (suwhitney):

Sorry, I am reading through it a couple times.. I'm still not getting it :/

OpenStudy (johnweldon1993):

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