Solve for B R=x(A+B) I am super confused, please help! (:
@abigailsimmons
You want to get the term that contains B isolated on one side of the equation. Here we start by determining which term contains B
What do you mean, @bibby ? I have had these types of problems before but I really don't understand this one
if we were solving for B A+B=C we'd subtract A from both sides to get B alone here we have \(R=x(A+B)\) now we have to divide both sides by x to get (A+B) alone (the term that contains B) \(\large \frac{R}{X}=A+B\)
Ohhhh...that starts to make snese... I think i got it
x(A+B) = x* (A+B) because the A+B is in parentheses it's easier to think of it as a single entity then we can do the opposite of division to both sides. so what do you think the answer is?
The answer would be B=(R-Ax)/x
Weird answer. what I did was \(R=x(A+B)\) divide both sides by x \(\huge \frac{R}{x}=\frac{}{\cancel{x}}\cancel{x}(A+B)\) \(\huge \frac{R}{x}-A=(B)\) subtract both sides by a
I don't see the point in getting A in terms of x, although as far as I can tell your answer is right
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