Sketch a graph of q as a function of p (i.e., q(p)), assuming that the focal length is a constant of 5 centimeters. Show any important features of the graph.
@freckles
Is there no sorta of equation given?
1/p +1/q=1/f
@freckles
oh okay so i think f represents your focal constant so replace f with 5 then solve 1/p+1/q=1/5 for q
p=35/2
q=5p/(p-5)
that bottom this is q written as a function of p with the focal constant as 5
yes
I had to solve this for another part of the question, I just don't know how to graph it now.
\[q=\frac{5p}{p-5}=\frac{5(p-5)+25}{p-5}=\frac{25}{p-5}+5\]
this should tell you the horizontal aysmotote and vertical asymptote?
no ? at the end
lol
you could think about the graph of y=1/x and translate it around to get the graph of y=1/(p-5)+5
So that is how you get the vertical and horizontal asymptotes but what about the rest of the graph?
do you know what y=1/x looks like?
yes
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