Ask
your own question, for FREE!
Ask question now!
Mathematics
4 Online
OpenStudy (nathanjhw):
Sketch a graph of q as a function of p (i.e., q(p)), assuming that the focal length is a constant of
5 centimeters. Show any important features of the graph.
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (nathanjhw):
@freckles
11 years ago
OpenStudy (freckles):
Is there no sorta of equation given?
11 years ago
OpenStudy (nathanjhw):
1/p +1/q=1/f
11 years ago
OpenStudy (nathanjhw):
@freckles
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (freckles):
oh okay so i think f represents your focal constant
so replace f with 5
then solve 1/p+1/q=1/5 for q
11 years ago
OpenStudy (nathanjhw):
p=35/2
11 years ago
OpenStudy (nathanjhw):
q=5p/(p-5)
11 years ago
OpenStudy (freckles):
that bottom this is q written as a function of p with the focal constant as 5
11 years ago
OpenStudy (nathanjhw):
yes
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (nathanjhw):
I had to solve this for another part of the question, I just don't know how to graph it now.
11 years ago
OpenStudy (freckles):
\[q=\frac{5p}{p-5}=\frac{5(p-5)+25}{p-5}=\frac{25}{p-5}+5\]
11 years ago
OpenStudy (freckles):
this should tell you the horizontal aysmotote and vertical asymptote?
11 years ago
OpenStudy (freckles):
no ? at the end
11 years ago
OpenStudy (freckles):
lol
11 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (freckles):
you could think about the graph of y=1/x and translate it around to get the graph of y=1/(p-5)+5
11 years ago
OpenStudy (nathanjhw):
So that is how you get the vertical and horizontal asymptotes but what about the rest of the graph?
11 years ago
OpenStudy (freckles):
do you know what y=1/x looks like?
11 years ago
OpenStudy (nathanjhw):
yes
11 years ago
OpenStudy (freckles):
|dw:1415065782313:dw|
11 years ago
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours! Join our real-time social learning platform and learn together with your friends!
Sign Up
Ask Question
Latest Questions
clllaaaaaire:
CLOSED
2 weeks ago
0 Replies
0 Medals