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Mathematics 19 Online
OpenStudy (anonymous):

Question Regarding Translation of Radical Functions

OpenStudy (anonymous):

So I have been taught that \[y - k = f(x - h) \] and the h signifies the translation of a graph horizontally. But I tested this out on a graphing calculator and have some problems. Say there was an equation like \[y = \sqrt{x - 2}\] That means that the base equation is translated 2 units right. But if the equation is something like \[y = \sqrt{-x - 2}\] Why is it that the graphing calculator shows that it is translated 2 units left and reflected on y axis? Should it not be 2 units right and reflected on y axis like the initial equation is.

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

start with \[\Large y = \sqrt{x}\] reflect it over the y axis by replacing each 'x' with '-x' \[\Large y = \sqrt{-x}\] if you want to move it 2 units to the left, you replace x with "x+2" \[\Large y = \sqrt{-(x+2)}\] \[\Large y = \sqrt{-x-2}\] ------------------------------------------------------- An alternative is to start with \[\Large y = \sqrt{x}\] then shift the graph 2 units to the right by replacing each 'x' with 'x-2' \[\Large y = \sqrt{x-2}\] then you reflect over the y axis by replacing each 'x' with '-x' \[\Large y = \sqrt{-x-2}\] and you get the same result as before

jimthompson5910 (jim_thompson5910):

the portion on the left that you see is the result AFTER the reflection over the y axis

OpenStudy (anonymous):

but in the base equation for reflection in the y axis is \[y = f \left( -x \right)\] this equation only affects x why is the h is affected

jimthompson5910 (jim_thompson5910):

h doesn't change though

jimthompson5910 (jim_thompson5910):

h = 2 the whole time in y = sqrt(x-2), it tells you to go right 2 units when it comes to y = sqrt(-x-2), you just flip everything. What is right is now left and vice versa

OpenStudy (anonymous):

you said \[y = \sqrt{- (x - h)} \] but isn't it \[y = \sqrt{-x - h}\] if you want to reflect in y axis

jimthompson5910 (jim_thompson5910):

well notice how I first reflected and then went left so I had -(x+2) and then it turns into -(x+2) ---> -x - 2

jimthompson5910 (jim_thompson5910):

in the end though, h is still 2

OpenStudy (anonymous):

yes therefore if h is = 2 then that means it is reflection to the right not left

OpenStudy (anonymous):

but graph shows: |dw:1415069039872:dw|

jimthompson5910 (jim_thompson5910):

let's start with sqrt(x) |dw:1415069123903:dw|

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