Question

sec(tan^-1(1))=

Answer 1

first tell me which angle of tan has a value of 1

Answer 2

\[\tan(?)=1\]

Answer 3

dont know

Answer 4

ok u need to know basic trig angle values to solve this problem
\[\tan45=1\]
so we can write it as
\[\sec(\tan^{-1}(1))=\sec(\tan^{-1}[\tan 45])\]

Answer 5

the answers are
1/2
\[\sqrt{3/2}\]

\[\sqrt{2}\]\[\sqrt{2}\]

Answer 6

yes let me explain to u a bit ok!!

Answer 7

we have to suppose the value?

Answer 8

ok

Answer 9

no these are standard values
check this out

Answer 10

ok

Answer 11

now we need another propery
\[\tan^{-1}(\tan~\theta)=\theta\]

Answer 12

so according to this property
\[\tan^{-1}(\tan~45^0)=?\]
can u tell me?

Answer 13

1

Answer 14

no
make sense?