Medals! The table shows data from a survey about the number of times families eat at restaurants during a week. The families are either from Rome, Italy or New York, New York:
How many times are you going to ask this?
As many times as I need until someone helps me. Its not against the law.
Which of the choices below best describes how to measure the center of this data? Both centers are best described with the mean. Both centers are best described with the median. The Rome data center is best described by the mean. The New York data center is best described by the median. The Rome data center is best described by the median. The New York data center is best described by the mean
It could be against OpenStudy rules...
Don't spam! Common forms of spam include: Posting a question multiple times within a short period of time. Posting a question that is off topic for a particular group (i.e. posting a physics question in the Mathematics group). Posting a reply that is not relevant to the topic of discussion within that question. Posting questions that are not, in fact, questions (for example, starting a question in the Mathematics group to wish someone "Happy Birthday"). Sending the same chat message repeatedly. <----- Read this Filing false abuse reports on a user repeatedly.
I thought it was against rule to repeatedly post the same thing without waiting. I waited and bumped it several times, so I on't think I'm doing anything wrong.
See? *short period of time*. It has been a long time.
Well I'm not sure. Let's ask @ganeshie8 ;)
Sure. All I'm saying is, I did nothing wrong. I ask for help, you get mad, and bombard me saying I did something wrong.
I didn't get mad. Did you see me get mad, @ganeshie8 ?
this looks like stats, im still searching for the question in above comments, whats the exact question that you're stuck on ?
If we could graph it would could easily see what the center would be..
nvm, found it
Thats what I'm stuck on, I don't really know how to graph it with this info. i just plot it down on the points just like that?
here is the rule : use mean if you have outlisers in the data use median in all other cases
do u see any outliers in the Rome data ?
I don't really think there are outliers... does 21 count as an outlier?
Notice that the Q3 is just 7.5, so any data around 20 is most likely an outlier
So they both have outliers, which mean the answer is A?
i gave u wrong rule earlier
here is the the corrected rule : use median if you have outlisers in the data use mean in all other cases
Oh... So it is B?
since you have outliers in both data, you use the robust central measure `median`
Yup !
use medain for both
Thank you! :D
yw :)
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