Question

Find the equation of the line with the given slope and containing the given point.
Slope -3/10 through (-4,0)

Answer 1

@SolomonZelman Can you help me with this one as well please?

Answer 2

y - y1 = m(x - x1)

plug in your numbers. (Please show your steps here)

Answer 3

y - 0 = m(x - -4)
y - 0 = -3/10 (x - -4)

Answer 4

can you finish it up?

Answer 5

(3/10) = m (-4-0)
y=3/10
x=-4
x1=0
@SolomonZelman

Answer 6

y - 0 = -3/10 (x - -4)
y = -3/10 (x - -4)
y = -3/10 (x+4)

Answer 7

can you finish this up?

Answer 8

Subtract 4 from both sides? @SolomonZelman

Answer 9

no, just expand the right side.

Answer 10

How do i do that @SolomonZelman

Answer 11

y=-3/4 4/10 right??? @SolomonZelman

Answer 12

@perl help?

Answer 13

y = -3/10 (x+4)
now distribute the -3/10

Answer 14

y = (-3/10) * x + (-3/10) * 4

Answer 15

I dont know if the 10 was right though @perl

Answer 16

it is correct

Answer 17

How do i distribute @perl ?

Answer 18

10y=-3(x+4)

Answer 19

10y= -3x-12

Answer 20

any one there

Answer 21

yes sorry

Answer 22

3x+10y+12=0 is the required eqn.
hope it will help you.

Answer 23

got it?

Answer 24

I dont know what to do after that?

Answer 25

after what step?

Answer 26

after what you just did

Answer 27

@mathmath333

Answer 28

pls tell the last step what you have got

Answer 29

marthaHearst

Answer 30

I couldnt figure out what to do..

Answer 31

you are given the slope of a line and point through which the line passes.
using slope intercept form
y-y1 = (slope)*(x-x1) here x1=-4 y1=0 m=-3/10
y-(0)=(-3/10)*(x-(-4)
till this clear?

Answer 32

any one?

Answer 33

\(\large\tt \begin{align} \color{black}{
m=\dfrac{-3}{10}\\
(x_1,y_1)=(-4,0)\\~\\
y-y_1=m(x-x_1)\\~~~\\~\\
y-0=\dfrac{-3}{10}(x-(-4)\\
y=\dfrac{-3}{10}(x+4)~~(\text{multily both sides by 10})\\~\\
10y=-3(x+4)~~(\text{solve the bracket on RHS})\\~\\
10y=-3x+(-3)(4)\\~\\
10y=-3x-12(~~\text{shift -3x to LHS})\\~\\
\huge 3x+10y=-12\\~\\
}\end{align}\)

this is the standard form of equation of straight line

Answer 34

its suppose to equal y though @mathmath333

Answer 35

@micahm @Hotchellerae21

Answer 36

re post question

Answer 37

Find the equation of the line with the given slope and containing the given point.
Slope -3/10 through (-4,0)

Answer 38

oh
then it would be

\(\Large y=\dfrac{-3}{10}(x+4)\\
\Large y=-\dfrac{3}{10}x+\dfrac{(-3\times 4)}{10}\\
\Large y=-\dfrac{3}{10}x-\dfrac{6}{5}\)

Answer 39

sound about right

Answer 40

@mathmath333 thank you so so so much, can you help me with another :)