Question

20x^3+49x^2+11x factor

Answer 1

can you (at first) take an x out? Tell me what you get after doing that.

Answer 2

20x+49 i dont get the factoring

Answer 3

\(\large\color{black}{ 20x^3+49x^2+11x}\)

each term is divisible by x, correct?

Answer 4

\(\large\color{black}{ 20x^3\div x = ?}\)
\(\large\color{black}{ 49x^2\div x = ?}\)
\(\large\color{black}{ 11x\div x = ?}\)

Answer 5

yes

Answer 6

can you tell me what do you get for each term, when you divide it (every term) by x?

Answer 7

the same number

Answer 8

\(\large\color{black}{ 20x^3+49x^2+11x}\)
would be,
\(\large\color{black}{ x(20x^2+49x+11)}\)

because when you divide \(\large\color{black}{ 20x^3+49x^2+11x}\)
you get, \(\large\color{black}{ 20x^2+49x+11}\)
and multiply that times x on the outside, not to change the value.

Answer 9

Sorry, I suck at explaining these...

Answer 10

no they hard! its ok thanks

Answer 11

you can think of a way to factor the,
\(\large\color{black}{ 20x^2+49x+11}\)

Answer 12

\(\large\color{black}{ (5x+~~~~)(4x+~~~~)}\)
what 2 numbers give you a product of 11, and sum of 49?

Answer 13

(they have to be factors of 11)

Answer 14

7, 11, nothng go into 11

Answer 15

only 1 and 11.

Answer 16

ok

Answer 17

\(\large\color{black}{ (5x+11)(4x+1)}\)

Answer 18

because 4*11=44 and 5*1=5, and 44+5=49

There is the middle term,
So, \(\large\color{black}{ x(20x^2+49x+11)}\)

becomes,
\(\large\color{black}{ x(5x+11)(4x+1)}\)

Answer 19

so why is there x on outside of problem?

Answer 20

because it was, \(\large\color{black}{ 20x^3+49x^2+11x}\)

we factored out of x, \(\large\color{black}{ x(20x^2+49x+11)}\)

and then factored the parenthesis, to get, \(\large\color{black}{ x(4x+1)(5x+11)}\)

Answer 21

ohh okthanks

Answer 22

Yw