Question

I really need help figuring out probability, for example...
USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x = number of prisoners out of five on parole who become repeat offenders.
0=.209 1=.377 2=.227 3=1.49 4=.037 5=.001
Find the probability that one or more of the five parolees will be repeat offenders. (Round your answer to three decimal places.)

Answer 1

Let X = # of parolees out of 5 prisoners paroled who become repeat offenders.

you want
P(X>= 1)

Answer 2

it is easier to do the complement.

P( A) = 1 - P ( A ' )

Answer 3

...still don't know how to figure this out

Answer 4

what goes where

Answer 5

P( X >= 1 ) = 1 - P ( X < 1 ) = 1 - P(x= 0)

Answer 6

do you agree so far?

Answer 7

yes

Answer 8

i am just planning out the theory, then i will plug in formula

Answer 9

ok we want the probability of

F F F F F (or S S S S S depending how you look at it )

Answer 10

F = fail, S = success

Answer 11

so we want
( prob. did not repeat offend) x ( prob. did not repeat offend)x( prob. did not repeat offend) x ( prob. did not repeat offend) x ( prob. did not repeat offend)

Answer 12

still lost