Question

Can someone pleasxe check my answer, thank Ya'll !!!! I chose "D"

Answer 1

I chose D

Answer 2

@e.mccormick

Answer 3

hmm what did you end up with the inequality? what's "x" inequals to? \(\large x \ge ?\)

Answer 4

well I got \[x \ge 0\] but that wasn't an option, im not sure how to do the math on this one :/

Answer 5

well... say....if you were to solve instead...

6-8x = 6(1+3x) + 6x

what would be your next step to solve for "x"?

Answer 6

okay here is my math for how i did it (after your step)

6-8x = (6*1)+(6*3x)+6x

6-8x = 6 + 18x +6x (combine all x terms)

6 = 6+ 32x

Answer 7

yeap there's a caveat in inequalities though when
multipliying or dividing or exponentializing by a negative value
you have to \(\bf flip\) the inequality sign

thus \(\bf 6-8x \ge 6(1+3x) + 6x\implies \cancel{ 6}-8x\ge \cancel{ 6 }+18x+6x
\\ \quad \\
-8x\ge 24x\implies -32\ge 0\implies x{\color{red}{ \le}}0\)

Answer 8

hmm missing an "x" there anyhow \(\bf 6-8x \ge 6(1+3x) + 6x\implies \cancel{ 6}-8x\ge \cancel{ 6 }+18x+6x
\\ \quad \\
-8x\ge 24x\implies -32x\ge 0\implies x{\color{red}{ \le}}0\)

Answer 9

okay i understand that and know how to do that, but how do yo uget -32 from \[-8x \ge 24x\]

Answer 10

\(\bf 6-8x \ge 6(1+3x) + 6x\implies \cancel{ 6}-8x\ge \cancel{ 6 }+18x+6x
\\ \quad \\
-8x\ge 24x\implies -8x-24x\ge \cancel{ 24x }\cancel{ -24x }\implies -32\ge 0\implies x{\color{red}{ \le}}0\)

Answer 11

ohhhhhh I get it now!! thank you so much!!!!

Answer 12

yw

Answer 13

\(\bf -32x\ge 0\implies x{\color{red}{ \le}}0\) had a missing"x" anyhow =)