Question

lim y^2
(x,y)->(0,0) /(x^8 +y^2)

Answer 1

Reformatted:
\[\lim_{(x,y) \rightarrow (0,0)}\frac{ y^2 }{ x^8 + y^2 }\]

Answer 2

Have you check to see what happens if we just had x->0
or if we just had y->0
or if we had (x,x)->(0,0)

Answer 3

using the fist two should work here

Answer 4

first*

Answer 5

\[\lim_{x \rightarrow 0}\frac{y^2}{x^8+y^2}=? \\ \lim_{y \rightarrow 0}\frac{y^2}{x^8+y^2}=?\]

Answer 6

Ah. Limit doesn't exist. It's 1 in the first case, but not in the second.

Answer 7

Thank you.

Answer 8

yep
lol that was fast

Answer 9

Good job you

Answer 10

http://www.sinclair.edu/centers/mathlab/pub/findyourcourse/worksheets/Calculus/LimitsOfFunctionsOfTwoVariables.pdf
I like this site by the way. You might too. It just has a couple of examples but I think it is is nice.

Answer 11

Nice. Thnaks