Question

Integral problem

Answer 1

\[\int\limits_{0}^{1} (x^e+e^x)\]

Answer 2

have no idea how to do this one

Answer 3

it is a trick

Answer 4

whats the trick?

Answer 5

trying to confuse you with \(x^e\)

Answer 6

the anti derivative of \(x^n\) is \[\frac{x^{n+1}}{n+1}\]

Answer 7

\[\int\limits_{ }^{ } e^x~dx=e^x~~~~~~~an d~~~~~~\int\limits_{ }^{ }x^e~dx=\frac{x^{e+1}}{e+1}\]

Answer 8

put \(n=e\) and you get
\[\frac{x^{e+1}}{e+1}\]

Answer 9

then subtract the sums.

Answer 10

okay i think i got it

Answer 11

can you say the answer, just in case?

Answer 12

the final answer is 1/(e+1) + e-1

Answer 13

i havent worked it out yet i just got it from the back of my book

Answer 14

yes

Answer 15

thank you solomonzelman

Answer 16

I think that plugging in the upper and lower limits and subtracting is not a problem.....
anytime!