Question

The lengths of the sides of a right triangle are a and b, and the hypotenuse is c. Find the area of the triangle.

a = 2 sqrt 3 ft.,c = 4 ft
A = sq. ft.

Answer 1

@Drakus

Answer 2

https://clackamasweb.owschools.com/media/g_geo_ccss_2014/8/groupi25.gif

Answer 3

here, we have a right angled triangle with a, b nd c as its sides.
a = base(b) = \[2\sqrt{3}\]
c= hypotenus (h) = 4 ft
so perpendicular(b) = \[\sqrt{h^{2}-b^{2}}\]
\[\sqrt{4^{2}-(2\sqrt{3)}^{2}}\]
\[\sqrt{16-12}\]
\[\sqrt{4}\]
= 2 ft
now,
Area of triangle = base*perpendicular/2
= \[2\sqrt{3}\times2\div2\]
\[4\sqrt{3}\div2\]
\[2\sqrt{3}\]

Answer 4

is the answer correct??????

Answer 5

yep thanks a lot:))

Answer 6

no mention dud....