someone please help me,
I have an idea of the answer. just wanna confirm
fam, medal, and testimony

Question

someone please help me,
I have an idea of the answer. just wanna confirm
fam, medal, and testimony

anonymous · Answer

attachment

anonymous · Answer

@myininaya

anonymous · Answer

find the slope of each function

the functions can be classified by their slopes, form larger value to smaller.

igreen · Answer

f(x) = (0, 0) and (4, 64)

g(x) = (0, -1) and (4, -3)

h(x) = (0, 18) and (4, 66)

Plug them into the formula $m = \dfrac{y_2-y_1}{x_2-x_1}$.

anonymous · Answer

how do I go about finding the slope? I completely forgot @rizwan_uet

anonymous · Answer

how you pick those specific numbers? @iGreen

igreen · Answer

I'll do the first one for you.

f(x) = (0, 0) and (4, 64)

$m = \dfrac{y_2-y_1}{x_2-x_1}$

$m = \dfrac{64-0}{4-0}$

$m = \dfrac{64}{4}$

$m = 16$

So the slope of f(x) is 16.

igreen · Answer

It tells you them..

igreen · Answer

See?

igreen · Answer

Can you find the slopes of the other two functions? @izthewiz7

anonymous · Answer

oooohhhhhh okay, hold on im going to figure this out

igreen · Answer

Okay, tell me the slopes when you're done.

anonymous · Answer

g(x)= -1

anonymous · Answer

h(x)= 12

igreen · Answer

No..g(x) is wrong..how did you get -1? You were close.

igreen · Answer

This is how you set up for g(x):

$m = \dfrac{y_2-y_1}{x_2-x_1}$

$m = \dfrac{-3-(-1)}{4-0}$

Simplify it:

$m = \dfrac{-3+1}{4-0}$

Can you finish it? @izthewiz7

igreen · Answer

I think you put $m = \dfrac{-3 - 1}{4-0}$, which would give you -1..but that's wrong.

igreen · Answer

And you got h(x) correct. :)

anonymous · Answer

yeah.. that's what I did for g(x) what did I do wrong?

igreen · Answer

You put $-3 - 1$ at the top instead of $-3 + 1$

Let me show you:

This is how you did it:

$m = \dfrac{y_2-y_1}{x_2-x_1}$

$m = \dfrac{-3-(-1)}{4-0}$

$m = \dfrac{-3-1}{4-0}$

$m = \dfrac{-4}{4}$

$m = -1$

Your mistake was here:

$m = \dfrac{y_2-y_1}{x_2-x_1}$

$m = \dfrac{-3-(-1)}{4-0}$

$m = \dfrac{-3\color{red}{-1}}{4-0}$

it should be:

$m = \dfrac{-3\color{red}{+1}}{4-0}$

igreen · Answer

Because a negative and a negative = a positive. Get it now?

igreen · Answer

Now can you finish g(x)?

Start from:

$m = \dfrac{-3 + 1}{4 - 0}$

anonymous · Answer

-1/2 ?

igreen · Answer

Yep!

So we have f(x) = 16, g(x) = -1/2, and h(x) = 12. Now what's the order from least to greatest? @izthewiz7

anonymous · Answer

g (x)= -1/2, h(x)= 12, f(x)=16 (((((:

igreen · Answer

Yep!! :D

igreen · Answer

Awesome work! Now you know how to do it in the future, hopefully. :)

igreen · Answer

@izthewiz7 If you want to learn more about slope, you can look at the tutorial I made on it: http://openstudy.com/study#/updates/5457ae42e4b0a717ff61bd1d

anonymous · Answer

thank you so much for everything! (:

igreen · Answer

No problem :) Just tag me if you need more help.