can someone help me please? ill give a medal.

Question

anonymous · Answer

sure

igreen · Answer

Question?

anonymous · Answer

Bill drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 10 hours. When Bill drove home, there was no traffic and the trip only took
7 hours. If his average rate was 18 miles per hour faster on the trip home, how far away does Bill live from the mountains?

Do not do any rounding.

igreen · Answer

Use the distance formula:

$d = rt$

Bill To Mountains:

$r \cdot 10 = d$

Bill to Home:

$(r + 12) \cdot 5 = d$

anonymous · Answer

ok?

anonymous · Answer

so would it be (18+12)*5

igreen · Answer

$\dfrac{D}{x} = 10, D = 10x$

Where x = rate to the mountains.

$\dfrac{10x}{x + 18}$

Therefore:

$7(x+18) = 10x$

Simplify:

$7x + 126 = 10x$

Subtract 7x to both sides:

$126 = 3x$

Divide 3 to both sides:

$x = 42$

So the rate to the mountains is 42 MPH.

Plug it back into the distance formula:

$D = rt$

$D = 10hr(42mph) = ?$

Can you multiply 10 * 42? @dontsmileurugly

anonymous · Answer

420

igreen · Answer

Yep, so the Mountains are 420 miles from his house.

anonymous · Answer

thank you!! can i ask another??

igreen · Answer

Sure, just close this one and open a new one.

anonymous · Answer

okay