Question

@iGreen

Answer 1

@iGreen

Answer 2

Do the same thing..use the Pythagorean Theorem.

\(a^2 + b^2 = c^2\)

\(8^2 + 14^2 = c^2\)

\(64 + 196 = c^2\)

\(260 = c^2\)

\(c = \sqrt{260}\)

Can you square 260? @blackops2luvr

Answer 3

Nvm, that's wrong..

Answer 4

lol ok if it as right it would have been 16.1245154966

Answer 5

well, 16

Answer 6

i need to reload brb \(\normalsize\sf\color{gold}{lol}\)

Answer 7

.

Answer 8

I think it's:

\(a^2 + b^2 = c^2\)

\(8^2 + b^2 = 14^2\)

\(64 + b^2 = 196\)

Subtract 64 to both sides:

\(b^2 = 132\)

\(b = \sqrt{132}\)

Can you square that?

Answer 9

sure. hold on

Answer 10

11.4891252931 Answer is D. 11.5

Answer 11

correct?

Answer 12

Yep!

Answer 13

yay :D

Answer 14

The legs of a right triangle are 18 centimeters and 80 centimeters long. What is the length of the hypotenuse?

82 centimeters
85 centimeters
89 centimeters
98 centimeters @iGreen , im just making sure im correct, i chose D.

Answer 15

\(a^2 + b^2 = c^2\)

\(18^2 + 80^2 = c^2\)

\(324 + 6400 = c^2\)

\(6724 = c^2\)

\(c = \sqrt{6724}\)

Can you square that?

Answer 16

a and b can be either legs..it doesn't matter which way you put them.

Answer 17

sqrt 6724 is 82