Factor x^2 + x - 20.
When factoring polynomials like this, you want to find factors of the c-value (in this case, -20), that also add up to the b-value (in this case, 1). What are the factors of -20?
-1 -2 -4 -5 -10 - 20
True, but also the positive values of those numbers. So the factors would be: \[\pm1,\pm2,\pm4,\pm5,\pm10, \pm20\]
Okay, so what two factors that equal -20 also add up to 1? For example, \(-1\times20=-20\), but \(-1+20\neq1\)
I honestly have no idea lol.
Well, you automatically can eliminate factors +-2 and +-10 because there is no way those numbers, which are so far apart, could ever add up to 1. So, what factors are you left with?
5 and 4
Correct. Since -20 is negative, you have these two pairs that equal -20 when multiplied: \(-4\times5\) and \(4\times-5\) Which pair adds up to 1?
the first one?
good job
so it'd be (x-4)(x+5)?
i belive it is
but i am not 100% sure
thank youuu
Yep, perfect
You're welcome. :)
then great job
you two
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