Is this tetrahedral too? @surry99
or is it hexagonal?
i think its hexagonal
Each carbon in the ring has 3 unique directions so the bond angles for those are 120 degrees so all the elements in the ring lie in the same plane. The shape of the ring is a hexagon. Now I am guessing the red element is oxygen...correct?
correct
So...would I can the shape hexagonal?
call^ not "can"
II would refer to the ring as hexagonal but lets talk about the -OH (called the hydroxyl group at the top) How many unique directions can you move from the oxygen...be careful with this one...
two?
is it a bent triatomic?
hint: are there any lone pairs of electrons on the oxygen?
yeah, one i think?
How would you determine of there are any lone pairs on the oxygen? What rule must it follow?
According to the Octet rule it would have to have 2 lone pairs...that means four unique directions from the oxygen...therefore it would be based on a tetrahedron
octet rule. one electron pair is connected tot he hydrogen, and one pair with the carbon, right? So, then two lone pairs?
yep|dw:1415229280968:dw|
So...this shape would be both hexagonal and tetrahedral?
The way they are asking your questions is odd to me... All the 6 carbon elements and their substituents lie in the ring ...so I would say the ring is hexagonal. But as we have seen , we would expect the angles around the oxygen to be near 109.5 ...So the -OH group is not in the same plane as the ring.
Okay, thank you. :)
Have you discussed hybridization in class yet?
would i draw the structural formula like this: |dw:1415229750924:dw| ?
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