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Find the orthogonal trajectories of the family of curves. x^2 + 2y^2 = k^2
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first find dy/dx yes?
im not sure if my dy/dx is correct.
i got |dw:1415231200845:dw|
that's right. So what is the slope that is perpendicular to that?
its 2y/x
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so dy/dx = 2y/x yes?
then i seperated the x and y's and got dy/2y = dx/x
ok, integrate then what do you get?
i got (1/2)ln(y) = 2(ln(x)) + C
not sure if thats right haha.
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should be (1/2) lny = lnx + C
oh yeah, i just simplified the y so i got 2(lnx + c)
then y = Ce^(2lnx)
but the book answer is different from this.
simplify further
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e^2lnx = 2?
OHHH
2LN X turns into lnx^2
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