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Mathematics 18 Online
OpenStudy (anonymous):

Limit question from calculus. Problem in comments

OpenStudy (anonymous):

OpenStudy (inkyvoyd):

divide top and bottom by n^3

OpenStudy (anonymous):

After I do that what do I do next?

OpenStudy (inkyvoyd):

well pretend n is a really large number... what does the expression equal?

OpenStudy (anonymous):

0? Is it nonexistant?

OpenStudy (inkyvoyd):

no... are you in precalculus or calculus?

OpenStudy (inkyvoyd):

it's a good idea to get a feeling for intuition here

OpenStudy (anonymous):

calculus lol. I'm taking an online course and I have no idea what I'm doing

OpenStudy (inkyvoyd):

you're looking at \(\Huge \frac{3-5/n^2}{1-2/n+1/n^3}\) as n becomes really large

OpenStudy (inkyvoyd):

that's what you get after you divide both sides by n^3

OpenStudy (anonymous):

Yeah I get that but I have to pick one of those answers

OpenStudy (inkyvoyd):

if you're going to always worry about which answer to pick you'll have a lot of answers to pick for your course... honestly if you wanted the answer you could've just looked it up on wolfram alpha

OpenStudy (inkyvoyd):

anyways you're interested in what happens when n becomes really, really big

OpenStudy (anonymous):

But I want to understand how to do it while getting the right answer.

OpenStudy (inkyvoyd):

so when n becomes really really big, some of the terms in that rational expression don't matter...

OpenStudy (inkyvoyd):

can you identify which ones?

OpenStudy (inkyvoyd):

by don't matter I mean that they approach zero.

OpenStudy (anonymous):

The denominator numbers?

OpenStudy (inkyvoyd):

well, let's try it out. Let's take n=1 first

OpenStudy (inkyvoyd):

\(\Huge \frac{3-5/n^2}{1-2/n+1/n^3}\)

OpenStudy (anonymous):

-2/0 is what I got

OpenStudy (inkyvoyd):

\(\Huge \frac{3-5/1^2}{1-2/1+1/1^3}\)=(3-5)/(1-2+1)=-2/((0)=undef

OpenStudy (inkyvoyd):

let's try it for n=10

OpenStudy (inkyvoyd):

\(\Huge \frac{3-5/10^2}{1-2/10+1/10^3}\)=3.6829

OpenStudy (inkyvoyd):

try it for n=100: we get 3.060711

OpenStudy (inkyvoyd):

try it for n=1000: we get 3.00600701102

OpenStudy (inkyvoyd):

try for n=10000: we get 3.00060007

OpenStudy (anonymous):

The higher to infinity we go it gets closer to 3. So as n approaches infinity we get 3

OpenStudy (inkyvoyd):

yes... now, let's see why

OpenStudy (inkyvoyd):

as n becomes larger and larger, the terms with n^2 and n in the denominator become closer and closer to zero

OpenStudy (inkyvoyd):

as n approaches infinity, these terms approach zero

OpenStudy (inkyvoyd):

and we are simply left with 3/1=3

OpenStudy (anonymous):

That makes so much sense now! Thank you so much.

OpenStudy (inkyvoyd):

np... just remember the rules you were taught in class: you have to divide by the term of the largest degree to be able to approach the problem like I did

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