I really need help with algebra! Which of the following is the solution set of -2|x| < -8 {x | -4 > x > 4} {x | -4 < x < 4} {x | x < -4 or x > 4}
Simplify \[-2|x| < -8\] by dividing both sides by -2 (remember to reveres the direction of inequality, because we are dividing by a negative )
so -2 divided by -8 is 2 then what
im mean 4 sorry
so >4
not quite, try that again
I really dont get it what do you mean divide both sides by two when i do that i get -1 and -4
thats better \[−2|x|<−8\\ −2|x|/-2<−8/-2\\ |x|>4\]
\(\large { -2|x| < -8\implies |x|{\color{red}{ >}}\cfrac{\cancel{ -8 }}{\cancel{ -2 }}\to 4 \\ \quad \\ |x|>4\to \begin{cases} +(x)>4\to &?\\ -(x)>4\to &? \end{cases} }\)
so is the answer number 1
1?
so is the answer the first option of the multiple choice
\(\large |x|>4\to \begin{cases} +(x)>4\to &x>4\\ -(x)>4\to &x{\color{red}{ <}}-4 \end{cases}\implies -4>x>4\) yes
no
then what is it??
@jdoe0001 was soooo close. Right up until the end.
well.... hmmm one could say, "or" conjunction I gather
think about the direction of those equality statements
ohh so its the third one
hmmm I don't see anything wrong heheh other than using "or" or not but someone knows, so that's good :)
-4>x>4 what does this supposed to mean? x is less than negative four, And greater that positive 4? impossible
so was i right
hmmmm depending on the scenario addressed... "x" can be less than a negative value and also greater than a positive one too
Yes. We want to illustrate that the solution is the set of numbers: |dw:1415235461318:dw|
there are no number that are negative And positive And greater in magnitude than four
the solution set has two branches
ooh ok i get it know =)) thx for your help
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