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Algebra
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OpenStudy (anonymous):
Can someone please help on this? I do not understand Geometric Sequences.
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OpenStudy (studygurl14):
What's your question?
OpenStudy (anonymous):
One sec, ataching the pic.
OpenStudy (anonymous):
OpenStudy (anonymous):
There's the problem.
OpenStudy (studygurl14):
Hm...sorry...I think this is out of my league. @TheSmartOne @Hero
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OpenStudy (inkyvoyd):
seems like the first one
OpenStudy (anonymous):
I'm good at math, but I'm stomped here.
OpenStudy (inkyvoyd):
notice how you're multiplying by 5/2 every time... so f(x)=some number
f(x+1)= some number times 5/2
f(x+2)=some number times 5/2 times 5/2
OpenStudy (inkyvoyd):
so it's the first one.
OpenStudy (freckles):
\[\frac{3}{2}, \frac{3}{2}(\frac{5}{2}), \frac{3}{2}(\frac{5}{2})^2, \frac{3}{2}(\frac{5}{2})^3, ..., \frac{3}{2}(\frac{5}{2})^{x-1}, \frac{3}{2}(\frac{5}{2})^{x}, ... \\ \text{ where } \\ f(1)=\frac{3}{2} \\ f(2)=\frac{3}{2}(\frac{5}{2}) \\ f(3)=\frac{3}{2}(\frac{5}{2})^2 \\ ... \\ f(x)=\frac{3}{2}(\frac{5}{2})^{x-1}\]
what is the f(x+1) value?
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OpenStudy (anonymous):
Thank you!
OpenStudy (anonymous):
Can you help me with more? >.<
OpenStudy (anonymous):
OpenStudy (anonymous):
@inkyvoyd
OpenStudy (inkyvoyd):
haha close this one and open a new question :)
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