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Algebra 7 Online
OpenStudy (anonymous):

Can someone please help on this? I do not understand Geometric Sequences.

OpenStudy (studygurl14):

What's your question?

OpenStudy (anonymous):

One sec, ataching the pic.

OpenStudy (anonymous):

OpenStudy (anonymous):

There's the problem.

OpenStudy (studygurl14):

Hm...sorry...I think this is out of my league. @TheSmartOne @Hero

OpenStudy (inkyvoyd):

seems like the first one

OpenStudy (anonymous):

I'm good at math, but I'm stomped here.

OpenStudy (inkyvoyd):

notice how you're multiplying by 5/2 every time... so f(x)=some number f(x+1)= some number times 5/2 f(x+2)=some number times 5/2 times 5/2

OpenStudy (inkyvoyd):

so it's the first one.

OpenStudy (freckles):

\[\frac{3}{2}, \frac{3}{2}(\frac{5}{2}), \frac{3}{2}(\frac{5}{2})^2, \frac{3}{2}(\frac{5}{2})^3, ..., \frac{3}{2}(\frac{5}{2})^{x-1}, \frac{3}{2}(\frac{5}{2})^{x}, ... \\ \text{ where } \\ f(1)=\frac{3}{2} \\ f(2)=\frac{3}{2}(\frac{5}{2}) \\ f(3)=\frac{3}{2}(\frac{5}{2})^2 \\ ... \\ f(x)=\frac{3}{2}(\frac{5}{2})^{x-1}\] what is the f(x+1) value?

OpenStudy (anonymous):

Thank you!

OpenStudy (anonymous):

Can you help me with more? >.<

OpenStudy (anonymous):

OpenStudy (anonymous):

@inkyvoyd

OpenStudy (inkyvoyd):

haha close this one and open a new question :)

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