Question

HELP ON CALCULUS

Answer 1

@satellite73 @ganeshie8

Answer 2

which problem ?

Answer 3

question 1 please

Answer 4

\[\log((x-1)(x-2))=\log(x-1)+\log(x-2)\] derivative is
\[\frac{1}{x-1}+\frac{1}{x-2}\] for example

Answer 5

what i meant to say was "log of the product is the sum of the logs"

Answer 6

so my solution becomes 1/(x-r1) + 1(x-r2) and continued?

Answer 7

correct

Answer 8

Thanks bro's

Answer 9

anyone help me with integration by parts quest please

Answer 10

@satellite73

Answer 11

@amistre64

Answer 12

what about a by parts?

Answer 13

i need to know to solve it

Answer 14

i dont see a by parts question ...

Answer 15

by parts assumes that the integral was created from a product rule

Answer 16

\[[uv]'=u'v+uv'\]
\[\int[uv]'=\int u'v+\int uv'\]
\[uv=\int u'v+\int uv'\]
\[\int uv'=uv-\int vu'\]

Answer 17

i know the formula, but i must know how to implement and execute it further though

Answer 18

u=z^n

Answer 19

dv= log z dz

Answer 20

integrating dv we can find v