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Mathematics 7 Online
OpenStudy (anonymous):

attaching graph PLEASE HELP EXAM TOMORROW (last question)

OpenStudy (anonymous):

can't wait to see this one

OpenStudy (anonymous):

OpenStudy (anonymous):

different procedure, same idea lets do \[f\circ g(-4)\]

OpenStudy (anonymous):

first we need \(g(-4)\) which you get from the graph what it it?

OpenStudy (anonymous):

if it is not clear, let me know, but it looks like you got this idea last time

OpenStudy (anonymous):

0

OpenStudy (anonymous):

ok good next we need \(f(0)\)

OpenStudy (anonymous):

why f(0)?

OpenStudy (anonymous):

once you find it i will explain clearly

OpenStudy (anonymous):

2

OpenStudy (anonymous):

ok right so what does \((f\circ g)(x)\) mean? it means \[f(g(x))\] without the circle notation that means \[(f\circ g)(-4)=f(g(-4))=f(0)=2\]

OpenStudy (anonymous):

not sure if that was clear as needed, but that is what it means, first find g of the number, then find f of the result want to try the next one?

OpenStudy (anonymous):

so because -4 is at 0 thats f(0)?

OpenStudy (anonymous):

yes because \(g(-4)=0\) then \(f(g(-4))=f(0)\)

OpenStudy (anonymous):

which in this case is \(f(0)=2\) so that is your "final answer"

OpenStudy (anonymous):

oh okay i see

OpenStudy (anonymous):

want to try the next one see if it is clear?

OpenStudy (anonymous):

yea, one question though. so g(x) will be x and f(x) will be y?

OpenStudy (anonymous):

yeah that is sort of one way to think about it

OpenStudy (anonymous):

oh wait nevermind

OpenStudy (anonymous):

it is really \[(f\circ g)(x)=f(g(x))\] so you need to compute \(g(x)\) first then take \(f\) of that result

OpenStudy (anonymous):

is the next one 4 then?

OpenStudy (anonymous):

hold on let me check with the picture

OpenStudy (anonymous):

yes you got it \[f(g(-6))=f(2)=4\]

OpenStudy (anonymous):

for the following two it the other way \[(g\circ f)(x)=g(f(x))\] so first \(f\) then \(g\) of that

OpenStudy (anonymous):

-5

OpenStudy (anonymous):

i got it :) thanks!

OpenStudy (anonymous):

yw good luck on the exam

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