attaching graph PLEASE HELP EXAM TOMORROW (last question)
can't wait to see this one
different procedure, same idea lets do \[f\circ g(-4)\]
first we need \(g(-4)\) which you get from the graph what it it?
if it is not clear, let me know, but it looks like you got this idea last time
0
ok good next we need \(f(0)\)
why f(0)?
once you find it i will explain clearly
2
ok right so what does \((f\circ g)(x)\) mean? it means \[f(g(x))\] without the circle notation that means \[(f\circ g)(-4)=f(g(-4))=f(0)=2\]
not sure if that was clear as needed, but that is what it means, first find g of the number, then find f of the result want to try the next one?
so because -4 is at 0 thats f(0)?
yes because \(g(-4)=0\) then \(f(g(-4))=f(0)\)
which in this case is \(f(0)=2\) so that is your "final answer"
oh okay i see
want to try the next one see if it is clear?
yea, one question though. so g(x) will be x and f(x) will be y?
yeah that is sort of one way to think about it
oh wait nevermind
it is really \[(f\circ g)(x)=f(g(x))\] so you need to compute \(g(x)\) first then take \(f\) of that result
is the next one 4 then?
hold on let me check with the picture
yes you got it \[f(g(-6))=f(2)=4\]
for the following two it the other way \[(g\circ f)(x)=g(f(x))\] so first \(f\) then \(g\) of that
-5
i got it :) thanks!
yw good luck on the exam
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