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Compute the unit vectors in the direction of |v1| and |v2|, where v1=(2,-6) v2=(-4,7) |v1|= 6.32 |v2|=8.06
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unit vector for v1 u1 = (v1)/(|v1|) unit vector for v2 u2 = (v2)/(|v2|)
it's equivalent to saying \[\Large u_1 = \frac{1}{|v_1|}*v_1\] \[\Large u_2 = \frac{1}{|v_2|}*v_2\]
So (2,-6)/6.32 and (-4,7)/8.06?
How would one use the point/vector over a real number?
well the portion 1/(|v1|) is a scalar
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so you have a scalar times a vector
c*<a,b> = <a*c, c*b>
Ah, so v1 would be (2/6.32, -6/6.32)?
correct
u1 actually
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My thanks, good sir
sure thing
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