Tutorial: Exponents
\(\bf\huge Basics:\) \(\large\color{red}{Base \rightarrow x}^{\color{blue}{a \leftarrow Exponent}}\) Exponents represent how many times the base is multiplied by itself. Example: \(2^5\) represents 2 being multiplied by itself 5 times. We can write this like \(2 \cdot 2 \cdot 2 \cdot 2\cdot 2 = 32\). Remember: All numbers have exponents, for example: \(5\) has an exponent of \(1\), even though we don’t write it. \(\bf\huge Rules:\) We cannot simplify exponents without like bases, unless we simplify them as whole numbers. \(\bf\small Multiplication~ Rule:\) When multiplying exponents with like bases, keep the base and add the exponents. \(x^\color{red}{a} \cdot x^\color{blue}{b} \rightarrow x^{\color{red}{a}+\color{blue}{b}}\) Examples: \(5^\color{red}{2} \cdot 5^\color{blue}{6} \rightarrow 5^{\color{red}{2}+\color{blue}{6}} \rightarrow 5^8\) \(4 \cdot 4^\color{blue}{3} \rightarrow 4^{\color{red}{1}+\color{blue}{3}} \rightarrow 4^4\) \(\bf\small Division ~Rule:\) When dividing exponents with like bases, keep the base and subtract the exponents. \(\dfrac{x^\color{red}{a}}{x^\color{blue}{b}} \rightarrow x^{\color{red}{a}-\color{blue}{b}}\) Examples: \(\dfrac{3^\color{red}{2}}{3^\color{blue}{3}} \rightarrow 3^{\color{red}{2}-\color{blue}{3}} \rightarrow 3^{-1}\) \(\dfrac{8^\color{red}{6}}{8^\color{blue}{2}} \rightarrow 8^{\color{red}{6}-\color{blue}{2}} \rightarrow 8^{4}\) \(\dfrac{2^\color{red}{2}}{2} \rightarrow 2^{\color{red}{2}-\color{blue}{1}} \rightarrow 2^{1}\) \(\bf\small Outside~ Exponent:\) When you have an exponent outside of a parenthesis, you multiply it with the exponents inside the parenthesis. \((x^\color{red}{a})^\color{blue}{b} \rightarrow x^{\color{red}{a} \cdot \color{blue}{b}}\) Examples: \((3^\color{red}{2})^\color{blue}{4} \rightarrow 3^{\color{red}{2} \cdot \color{blue}{4}} \rightarrow 3^8\) \((x^\color{red}{2}y^\color{blue}{3})^\color{lime}{2} \rightarrow x^{\color{red}{2 \cdot \color{lime}{2}}} y^{\color{blue}{3} \cdot \color{lime}{2}} \rightarrow x^4y^6\) \((xy^\color{blue}{2})^\color{lime}{4} \rightarrow x^{\color{red}{1 \cdot \color{lime}{4}}} y^{\color{blue}{2} \cdot \color{lime}{4}} \rightarrow x^4y^8\) \((\dfrac{x^\color{red}2}{y^\color{blue}3})^\color{lime}5 \rightarrow \dfrac{x^{\color{red}2 \cdot \color{lime}5}}{ y^{\color{blue}3 \cdot \color{lime}5}} \rightarrow \dfrac{x^{10}}{y^{15}}\) \(\bf\small Power~ of ~Zero:\) Anything to the power of Zero equals 1. \(x^0 = 1\) Examples: \(5^0 = 1\) \([(x^3y^5z^6)(x^{-5}y^2z^{11})]^0 = 1\) \(\bf\small Negative~ Exponents:\) \(\color{red}x^{-\color{blue}1} \rightarrow \dfrac{\color{blue}1}{\color{red}x}\) \(\color{red}x^{-\color{blue}a} \rightarrow \dfrac{1}{\color{red}x^{\color{blue}a}}\) Examples: \(\color{red}4^{-\color{blue}1} \rightarrow \dfrac{\color{blue}1}{\color{red}4}\) \(\color{red}3^{-\color{blue}4} \rightarrow \dfrac{1}{\color{red}3^{\color{blue}4}}\)
Explain it. Why does x^0=1?
Suppose you have \[\LARGE x^3*x^2\] is there a way we can simplify this? Well exponents just tell us how many times something is multiplied together, so we can rewrite it like that: \[\LARGE (x*x*x)*(x*x)\] but this is just 5 x's multiplied together so we get: \[\LARGE x^5\] So we can pretty clearly see that this pattern will hold: \[\LARGE x^ax^b=x^{a+b}\] Now let's suppose we have this fraction\[\LARGE \frac{x^3}{x^2}=\frac{x*x*x}{x*x}=x\] we just divided them all out. It looks like division follows a similar rule, we should subtract the bottom one from the top one since \[\LARGE x^{3-2}=x^1\] Now from this observation we can also see two cool observations: if we have: \[\LARGE \frac{x^2}{x^2}=x^{2-2}=x^0\] so since anything divided by itself is 1, then by looking at these rules we just discovered we can also see that x^0=1 interesting! Also, what if there is nothing on top? Then we just have: \[\LARGE \frac{1}{x^3}=x^{0-3}=x^{-3}\] One last thing we should try to find out is what if we have something like this: \[\Large(x^2)^3=x^2*x^2*x^2=(x*x)(x*x)(x*x)=x^6\] so we can see that we just multiplied 2*3=6. So we can figure it all out and it all has a reason for being this way as you can see by playing around with examples and testing it out.
Anything `except 0,` to the power of Zero equals 1
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