the average of three cosective integer such that twice the greatest integer is 2 less than times the least integer
@I_Need_Help_With_Home
@waterineyes
Let the three consecutive numbers be : \((x-1)\), \(x\), \((x+1)\)
ok
Average of three numbers is given by: \[Average = \frac{\tt {Sum \ of \ three \ numbers}}{\tt{Number \ of \ Numbers}}\]
right
As you have three numbers, so their sum would be: \(Sum = x-1 + x + x+1\) implies \(Sum = 3x\)
And as you have three numbers, so number of numbers are \(3\).
And you have also one relation given in question, we try to use that. out of that three numbers, \((x+1)\) would be greatest of all, and \((x-1)\) will be smallest number.
And the relation is: \(2(x+1) = 2(x-1) + 2\)
Sorry: \(2(x+1) = 2(x-1) - 2\)
Can you find out \(x\) from here?
yes
Then find out \(x\), and tell me.
less than 3 times the least integer ??
@waterineyes the average of three cosective integer such that twice the greatest integer is 2 less than3 times the least integer
3?
Then it would be: \(2(x+1) = 3(x-1)-2\)
Can you find \(x\) here now?
@rosebird doing?
tag me when you are done. :)
yeh
why 3 befor bracket??
why u put 3 before bracket? @waterineyes
7? is answer :) ty @waterineyes
3 times the least integer means 3 multiplied by least integer and least integer is \((x-1)\). So, \(3 \times (x-1)\)
\(x =7\), but it is \(x\) value. Now we have to find Average.
but the answers are 6 7 8
I already calculated above that sum is \(3x\) and number of numbers you have is \(3\): So: \[Average = \frac{Sum}{Total number} = \frac{3x}{3} \implies \color{green}{Average = x}\]
It is your luck that value of \(x\) is average itself. :P
hahaha thanks:) @waterineyes
Do you want to know how \(x\) is average itself?
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